Base | Representation |
---|---|
bin | 111010110101011100011… |
… | …001000111100101111111 |
3 | 112022111222120212210020201 |
4 | 322311130121013211333 |
5 | 1012220244231022421 |
6 | 12333214151224331 |
7 | 565051066426645 |
oct | 72653431074577 |
9 | 15274876783221 |
10 | 4043114314111 |
11 | 1319747698a24 |
12 | 5536ba9780a7 |
13 | 2343581483c2 |
14 | dd98b38d195 |
15 | 702860b6b91 |
hex | 3ad5c64797f |
4043114314111 has 2 divisors, whose sum is σ = 4043114314112. Its totient is φ = 4043114314110.
The previous prime is 4043114314103. The next prime is 4043114314139. The reversal of 4043114314111 is 1114134113404.
It is an a-pointer prime, because the next prime (4043114314139) can be obtained adding 4043114314111 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4043114314111 - 23 = 4043114314103 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4043114314111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4043114314181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021557157055 + 2021557157056.
It is an arithmetic number, because the mean of its divisors is an integer number (2021557157056).
Almost surely, 24043114314111 is an apocalyptic number.
4043114314111 is a deficient number, since it is larger than the sum of its proper divisors (1).
4043114314111 is an equidigital number, since it uses as much as digits as its factorization.
4043114314111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 4043114314111 its reverse (1114134113404), we get a palindrome (5157248427515).
The spelling of 4043114314111 in words is "four trillion, forty-three billion, one hundred fourteen million, three hundred fourteen thousand, one hundred eleven".
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