Base | Representation |
---|---|
bin | 111010110101011100111… |
… | …110110101011101010101 |
3 | 112022112000021111002220221 |
4 | 322311130332311131111 |
5 | 1012220304243420201 |
6 | 12333215143154341 |
7 | 565051246446403 |
oct | 72653476653525 |
9 | 15275007432827 |
10 | 4043124201301 |
11 | 1319752231359 |
12 | 5537021459b1 |
13 | 23435a1ca803 |
14 | dd98c804473 |
15 | 70286dbb4a1 |
hex | 3ad5cfb5755 |
4043124201301 has 2 divisors, whose sum is σ = 4043124201302. Its totient is φ = 4043124201300.
The previous prime is 4043124201143. The next prime is 4043124201379. The reversal of 4043124201301 is 1031024213404.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4026640209201 + 16483992100 = 2006649^2 + 128390^2 .
It is a cyclic number.
It is not a de Polignac number, because 4043124201301 - 221 = 4043122104149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4043124201101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021562100650 + 2021562100651.
It is an arithmetic number, because the mean of its divisors is an integer number (2021562100651).
Almost surely, 24043124201301 is an apocalyptic number.
It is an amenable number.
4043124201301 is a deficient number, since it is larger than the sum of its proper divisors (1).
4043124201301 is an equidigital number, since it uses as much as digits as its factorization.
4043124201301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4043124201301 its reverse (1031024213404), we get a palindrome (5074148414705).
The spelling of 4043124201301 in words is "four trillion, forty-three billion, one hundred twenty-four million, two hundred one thousand, three hundred one".
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