Base | Representation |
---|---|
bin | 10010011010101101110001… |
… | …00100101111011011010011 |
3 | 12022101210110120001210211011 |
4 | 21031112320210233123103 |
5 | 20302024200334220141 |
6 | 222045333441031351 |
7 | 11350024155512455 |
oct | 1115267044573323 |
9 | 168353416053734 |
10 | 40500343273171 |
11 | 119a510aa32801 |
12 | 46612a3025557 |
13 | 197a220884952 |
14 | a003271382d5 |
15 | 4a3790a5a881 |
hex | 24d5b892f6d3 |
40500343273171 has 2 divisors, whose sum is σ = 40500343273172. Its totient is φ = 40500343273170.
The previous prime is 40500343273133. The next prime is 40500343273211. The reversal of 40500343273171 is 17137234300504.
It is a happy number.
It is an a-pointer prime, because the next prime (40500343273211) can be obtained adding 40500343273171 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40500343273171 - 27 = 40500343273043 is a prime.
It is not a weakly prime, because it can be changed into another prime (40500343273111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20250171636585 + 20250171636586.
It is an arithmetic number, because the mean of its divisors is an integer number (20250171636586).
Almost surely, 240500343273171 is an apocalyptic number.
40500343273171 is a deficient number, since it is larger than the sum of its proper divisors (1).
40500343273171 is an equidigital number, since it uses as much as digits as its factorization.
40500343273171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 211680, while the sum is 40.
Adding to 40500343273171 its reverse (17137234300504), we get a palindrome (57637577573675).
The spelling of 40500343273171 in words is "forty trillion, five hundred billion, three hundred forty-three million, two hundred seventy-three thousand, one hundred seventy-one".
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