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40504151533133 is a prime number
BaseRepresentation
bin10010011010110100110111…
…00100000110011001001101
312022102011021221222110101102
421031122123210012121031
520302110000243030013
6222051203401152445
711350220430263261
oct1115323344063115
9168364257873342
1040504151533133
11119a6794665892
124661b8648b725
13197a6a9851902
14a005a8c1a0a1
154a3915058d58
hex24d69b90664d

40504151533133 has 2 divisors, whose sum is σ = 40504151533134. Its totient is φ = 40504151533132.

The previous prime is 40504151533057. The next prime is 40504151533151. The reversal of 40504151533133 is 33133515140504.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33405140159524 + 7099011373609 = 5779718^2 + 2664397^2 .

It is a cyclic number.

It is not a de Polignac number, because 40504151533133 - 222 = 40504147338829 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40504151533163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20252075766566 + 20252075766567.

It is an arithmetic number, because the mean of its divisors is an integer number (20252075766567).

Almost surely, 240504151533133 is an apocalyptic number.

It is an amenable number.

40504151533133 is a deficient number, since it is larger than the sum of its proper divisors (1).

40504151533133 is an equidigital number, since it uses as much as digits as its factorization.

40504151533133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162000, while the sum is 38.

Adding to 40504151533133 its reverse (33133515140504), we get a palindrome (73637666673637).

The spelling of 40504151533133 in words is "forty trillion, five hundred four billion, one hundred fifty-one million, five hundred thirty-three thousand, one hundred thirty-three".