Base | Representation |
---|---|
bin | 111010111101001001100… |
… | …001010000011011011111 |
3 | 112100022100011120000102001 |
4 | 322331021201100123133 |
5 | 1012334220212134233 |
6 | 12341103132543131 |
7 | 565463106346354 |
oct | 72751141203337 |
9 | 15308304500361 |
10 | 4051387614943 |
11 | 1322202764329 |
12 | 555229621aa7 |
13 | 23507619b896 |
14 | 10013407a62b |
15 | 705bc59a27d |
hex | 3af498506df |
4051387614943 has 2 divisors, whose sum is σ = 4051387614944. Its totient is φ = 4051387614942.
The previous prime is 4051387614941. The next prime is 4051387615021. The reversal of 4051387614943 is 3494167831504.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4051387614943 - 21 = 4051387614941 is a prime.
Together with 4051387614941, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4051387614941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2025693807471 + 2025693807472.
It is an arithmetic number, because the mean of its divisors is an integer number (2025693807472).
Almost surely, 24051387614943 is an apocalyptic number.
4051387614943 is a deficient number, since it is larger than the sum of its proper divisors (1).
4051387614943 is an equidigital number, since it uses as much as digits as its factorization.
4051387614943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8709120, while the sum is 55.
The spelling of 4051387614943 in words is "four trillion, fifty-one billion, three hundred eighty-seven million, six hundred fourteen thousand, nine hundred forty-three".
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