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405211314254231 is a prime number
BaseRepresentation
bin101110000100010011001110…
…0011100011111000110010111
31222010201211020012102121001102
41130020212130130133012113
5411102440232422113411
63553451301413220315
7151231360054132442
oct13410463434370627
91863654205377042
10405211314254231
11108127176071a91
123954480133169b
13145143559a7674
14720c4919c6659
1531ca72223ad3b
hex170899c71f197

405211314254231 has 2 divisors, whose sum is σ = 405211314254232. Its totient is φ = 405211314254230.

The previous prime is 405211314254207. The next prime is 405211314254251. The reversal of 405211314254231 is 132452413112504.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 405211314254231 - 218 = 405211313992087 is a prime.

It is a super-2 number, since 2×4052113142542312 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (405211314254251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202605657127115 + 202605657127116.

It is an arithmetic number, because the mean of its divisors is an integer number (202605657127116).

Almost surely, 2405211314254231 is an apocalyptic number.

405211314254231 is a deficient number, since it is larger than the sum of its proper divisors (1).

405211314254231 is an equidigital number, since it uses as much as digits as its factorization.

405211314254231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 115200, while the sum is 38.

Adding to 405211314254231 its reverse (132452413112504), we get a palindrome (537663727366735).

The spelling of 405211314254231 in words is "four hundred five trillion, two hundred eleven billion, three hundred fourteen million, two hundred fifty-four thousand, two hundred thirty-one".