Base | Representation |
---|---|
bin | 111010111101110101111… |
… | …101100110101001000101 |
3 | 112100101021010120212110002 |
4 | 322331311331212221011 |
5 | 1012342232102242321 |
6 | 12341305130211045 |
7 | 565520432160422 |
oct | 72756575465105 |
9 | 15311233525402 |
10 | 4052133243461 |
11 | 1322555639046 |
12 | 5553b7283a85 |
13 | 2351647c56a4 |
14 | 1001a50d0d49 |
15 | 70612c8220b |
hex | 3af75f66a45 |
4052133243461 has 2 divisors, whose sum is σ = 4052133243462. Its totient is φ = 4052133243460.
The previous prime is 4052133243427. The next prime is 4052133243469. The reversal of 4052133243461 is 1643423312504.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4044800746561 + 7332496900 = 2011169^2 + 85630^2 .
It is a cyclic number.
It is not a de Polignac number, because 4052133243461 - 218 = 4052132981317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4052133243469) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2026066621730 + 2026066621731.
It is an arithmetic number, because the mean of its divisors is an integer number (2026066621731).
Almost surely, 24052133243461 is an apocalyptic number.
It is an amenable number.
4052133243461 is a deficient number, since it is larger than the sum of its proper divisors (1).
4052133243461 is an equidigital number, since it uses as much as digits as its factorization.
4052133243461 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 207360, while the sum is 38.
Adding to 4052133243461 its reverse (1643423312504), we get a palindrome (5695556555965).
The spelling of 4052133243461 in words is "four trillion, fifty-two billion, one hundred thirty-three million, two hundred forty-three thousand, four hundred sixty-one".
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