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40540105422413 is a prime number
BaseRepresentation
bin10010011011110111110101…
…00101010011011001001101
312022112121002122120021102022
421031323322211103121031
520303202113442004123
6222115511201535525
711352632414302022
oct1115737245233115
9168477078507368
1040540105422413
1111a0aa646a5a73
124668b3b3445a5
131980bb95896cc
14a02219cad549
154a481b70d1c8
hex24defa95364d

40540105422413 has 2 divisors, whose sum is σ = 40540105422414. Its totient is φ = 40540105422412.

The previous prime is 40540105422371. The next prime is 40540105422469. The reversal of 40540105422413 is 31422450104504.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24084410162569 + 16455695259844 = 4907587^2 + 4056562^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40540105422413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40540105422473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20270052711206 + 20270052711207.

It is an arithmetic number, because the mean of its divisors is an integer number (20270052711207).

Almost surely, 240540105422413 is an apocalyptic number.

It is an amenable number.

40540105422413 is a deficient number, since it is larger than the sum of its proper divisors (1).

40540105422413 is an equidigital number, since it uses as much as digits as its factorization.

40540105422413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 76800, while the sum is 35.

Adding to 40540105422413 its reverse (31422450104504), we get a palindrome (71962555526917).

The spelling of 40540105422413 in words is "forty trillion, five hundred forty billion, one hundred five million, four hundred twenty-two thousand, four hundred thirteen".