Base | Representation |
---|---|
bin | 100101110001000010… |
… | …010000000101001111 |
3 | 10212200002002101200221 |
4 | 211301002100011033 |
5 | 1131022041334411 |
6 | 30343503132211 |
7 | 2633615562145 |
oct | 456102200517 |
9 | 125602071627 |
10 | 40551121231 |
11 | 1621a061635 |
12 | 7a385a4067 |
13 | 3a932c61ba |
14 | 1d6986d595 |
15 | 10c509c071 |
hex | 97109014f |
40551121231 has 2 divisors, whose sum is σ = 40551121232. Its totient is φ = 40551121230.
The previous prime is 40551121189. The next prime is 40551121253. The reversal of 40551121231 is 13212115504.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40551121231 - 29 = 40551120719 is a prime.
It is a super-2 number, since 2×405511212312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 40551121196 and 40551121205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40551121271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20275560615 + 20275560616.
It is an arithmetic number, because the mean of its divisors is an integer number (20275560616).
Almost surely, 240551121231 is an apocalyptic number.
40551121231 is a deficient number, since it is larger than the sum of its proper divisors (1).
40551121231 is an equidigital number, since it uses as much as digits as its factorization.
40551121231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 40551121231 its reverse (13212115504), we get a palindrome (53763236735).
The spelling of 40551121231 in words is "forty billion, five hundred fifty-one million, one hundred twenty-one thousand, two hundred thirty-one".
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