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405540411433 is a prime number
BaseRepresentation
bin1011110011011000001…
…01111001100000101001
31102202202210211102200021
411321230011321200221
523121021321131213
6510145214240441
741204445423013
oct5715405714051
91382683742607
10405540411433
11146a96a98523
126671a7b6121
132c31c430bc1
14158b1d391b3
15a837eebd8d
hex5e6c179829

405540411433 has 2 divisors, whose sum is σ = 405540411434. Its totient is φ = 405540411432.

The previous prime is 405540411431. The next prime is 405540411443. The reversal of 405540411433 is 334114045504.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 354463055424 + 51077356009 = 595368^2 + 226003^2 .

It is a cyclic number.

It is not a de Polignac number, because 405540411433 - 21 = 405540411431 is a prime.

It is a super-2 number, since 2×4055404114332 (a number of 24 digits) contains 22 as substring.

Together with 405540411431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (405540411431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202770205716 + 202770205717.

It is an arithmetic number, because the mean of its divisors is an integer number (202770205717).

Almost surely, 2405540411433 is an apocalyptic number.

It is an amenable number.

405540411433 is a deficient number, since it is larger than the sum of its proper divisors (1).

405540411433 is an equidigital number, since it uses as much as digits as its factorization.

405540411433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 34.

Adding to 405540411433 its reverse (334114045504), we get a palindrome (739654456937).

The spelling of 405540411433 in words is "four hundred five billion, five hundred forty million, four hundred eleven thousand, four hundred thirty-three".