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40597626142133 is a prime number
BaseRepresentation
bin10010011101100010111110…
…00101011011110110110101
312022202002120100221120222222
421032301133011123312311
520310122414243022013
6222202143022332125
711360040010325234
oct1116613705336665
9168662510846888
1040597626142133
1111a323a1641065
124678112a2a045
131986455490338
14a04d15386b1b
154a6086479508
hex24ec5f15bdb5

40597626142133 has 2 divisors, whose sum is σ = 40597626142134. Its totient is φ = 40597626142132.

The previous prime is 40597626142127. The next prime is 40597626142189. The reversal of 40597626142133 is 33124162679504.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 34157923092484 + 6439703049649 = 5844478^2 + 2537657^2 .

It is a cyclic number.

It is not a de Polignac number, because 40597626142133 - 210 = 40597626141109 is a prime.

It is a super-3 number, since 3×405976261421333 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40597626142193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20298813071066 + 20298813071067.

It is an arithmetic number, because the mean of its divisors is an integer number (20298813071067).

Almost surely, 240597626142133 is an apocalyptic number.

It is an amenable number.

40597626142133 is a deficient number, since it is larger than the sum of its proper divisors (1).

40597626142133 is an equidigital number, since it uses as much as digits as its factorization.

40597626142133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6531840, while the sum is 53.

The spelling of 40597626142133 in words is "forty trillion, five hundred ninety-seven billion, six hundred twenty-six million, one hundred forty-two thousand, one hundred thirty-three".