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40613514127 is a prime number
BaseRepresentation
bin100101110100110000…
…010000101110001111
310212211102111021122221
4211310300100232033
51131134024423002
630354012320211
72635304113504
oct456460205617
9125742437587
1040613514127
11162512a730a
127a55473067
133aa3200384
141d73c714ab
1510ca7c3c37
hex974c10b8f

40613514127 has 2 divisors, whose sum is σ = 40613514128. Its totient is φ = 40613514126.

The previous prime is 40613514119. The next prime is 40613514143. The reversal of 40613514127 is 72141531604.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 40613514127 - 23 = 40613514119 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40613514092 and 40613514101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40613514827) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20306757063 + 20306757064.

It is an arithmetic number, because the mean of its divisors is an integer number (20306757064).

Almost surely, 240613514127 is an apocalyptic number.

40613514127 is a deficient number, since it is larger than the sum of its proper divisors (1).

40613514127 is an equidigital number, since it uses as much as digits as its factorization.

40613514127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 34.

The spelling of 40613514127 in words is "forty billion, six hundred thirteen million, five hundred fourteen thousand, one hundred twenty-seven".