Base | Representation |
---|---|
bin | 100101110101001001… |
… | …011011110011110111 |
3 | 10212211212220112210221 |
4 | 211311021123303313 |
5 | 1131142222110033 |
6 | 30354405555211 |
7 | 2635414156561 |
oct | 456511336367 |
9 | 125755815727 |
10 | 40620113143 |
11 | 16254aa4245 |
12 | 7a57715b07 |
13 | 3aa46a0c0c |
14 | 1d74aac331 |
15 | 10cb17912d |
hex | 97525bcf7 |
40620113143 has 2 divisors, whose sum is σ = 40620113144. Its totient is φ = 40620113142.
The previous prime is 40620113119. The next prime is 40620113173. The reversal of 40620113143 is 34131102604.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40620113143 - 25 = 40620113111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40620113173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20310056571 + 20310056572.
It is an arithmetic number, because the mean of its divisors is an integer number (20310056572).
Almost surely, 240620113143 is an apocalyptic number.
40620113143 is a deficient number, since it is larger than the sum of its proper divisors (1).
40620113143 is an equidigital number, since it uses as much as digits as its factorization.
40620113143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 40620113143 its reverse (34131102604), we get a palindrome (74751215747).
The spelling of 40620113143 in words is "forty billion, six hundred twenty million, one hundred thirteen thousand, one hundred forty-three".
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