4065512113151 has 2 divisors, whose sum is σ = 4065512113152. Its totient is φ = 4065512113150.

The previous prime is 4065512113139. The next prime is 4065512113153. The reversal of 4065512113151 is 1513112155604.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4065512113151 - 2²⁶ = 4065445004287 is a prime.

Together with 4065512113153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4065512113153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2032756056575 + 2032756056576.

It is an arithmetic number, because the mean of its divisors is an integer number (2032756056576).

Almost surely, 2^{4065512113151} is an apocalyptic number.

4065512113151 is a deficient number, since it is larger than the sum of its proper divisors (1).

4065512113151 is an equidigital number, since it uses as much as digits as its factorization.

4065512113151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 35.

Adding to 4065512113151 its reverse (1513112155604), we get a palindrome (5578624268755).

The spelling of 4065512113151 in words is "four trillion, sixty-five billion, five hundred twelve million, one hundred thirteen thousand, one hundred fifty-one".