Base | Representation |
---|---|
bin | 1111001010001100… |
… | …1110000111001101 |
3 | 101111121010211101212 |
4 | 3302203032013031 |
5 | 31313221202432 |
6 | 1511443344205 |
7 | 202561433063 |
oct | 36243160715 |
9 | 11447124355 |
10 | 4069319117 |
11 | 17a902a756 |
12 | 956982065 |
13 | 4cb0b2346 |
14 | 2a863a033 |
15 | 18c3b92b2 |
hex | f28ce1cd |
4069319117 has 2 divisors, whose sum is σ = 4069319118. Its totient is φ = 4069319116.
The previous prime is 4069319029. The next prime is 4069319119. The reversal of 4069319117 is 7119139604.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3920137321 + 149181796 = 62611^2 + 12214^2 .
It is a cyclic number.
It is not a de Polignac number, because 4069319117 - 218 = 4069056973 is a prime.
Together with 4069319119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4069319119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2034659558 + 2034659559.
It is an arithmetic number, because the mean of its divisors is an integer number (2034659559).
Almost surely, 24069319117 is an apocalyptic number.
It is an amenable number.
4069319117 is a deficient number, since it is larger than the sum of its proper divisors (1).
4069319117 is an equidigital number, since it uses as much as digits as its factorization.
4069319117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40824, while the sum is 41.
The square root of 4069319117 is about 63791.2150456472. The cubic root of 4069319117 is about 1596.5183560351.
The spelling of 4069319117 in words is "four billion, sixty-nine million, three hundred nineteen thousand, one hundred seventeen".
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