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408312161261 is a prime number
BaseRepresentation
bin1011111000100010100…
…11010010001111101101
31110000220222100220122022
411330101103102033231
523142210403130021
6511324230355525
741333233051214
oct5742123221755
91400828326568
10408312161261
11148189630164
1267172abbba5
132c671749764
1415a960c807b
15a94b5061ab
hex5f114d23ed

408312161261 has 2 divisors, whose sum is σ = 408312161262. Its totient is φ = 408312161260.

The previous prime is 408312161239. The next prime is 408312161263. The reversal of 408312161261 is 162161213804.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 397416768100 + 10895393161 = 630410^2 + 104381^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-408312161261 is a prime.

It is a super-2 number, since 2×4083121612612 (a number of 24 digits) contains 22 as substring.

Together with 408312161263, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (408312161263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 204156080630 + 204156080631.

It is an arithmetic number, because the mean of its divisors is an integer number (204156080631).

Almost surely, 2408312161261 is an apocalyptic number.

It is an amenable number.

408312161261 is a deficient number, since it is larger than the sum of its proper divisors (1).

408312161261 is an equidigital number, since it uses as much as digits as its factorization.

408312161261 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 35.

The spelling of 408312161261 in words is "four hundred eight billion, three hundred twelve million, one hundred sixty-one thousand, two hundred sixty-one".