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40851214848053 is a prime number
BaseRepresentation
bin10010100100111011010100…
…01001100101000000110101
312100122100010101211121011022
421102131222021211000311
520323301242000114203
6222514442232350525
711414255120630411
oct1122355211450065
9170570111747138
1040851214848053
111201a9a287a175
1246b92a5245445
1319a4339ba674c
14a132d0647d41
154ac979373a38
hex25276a265035

40851214848053 has 2 divisors, whose sum is σ = 40851214848054. Its totient is φ = 40851214848052.

The previous prime is 40851214847969. The next prime is 40851214848107. The reversal of 40851214848053 is 35084841215804.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40700342421124 + 150872426929 = 6379682^2 + 388423^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40851214848053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40851214847986 and 40851214848004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40851214845053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20425607424026 + 20425607424027.

It is an arithmetic number, because the mean of its divisors is an integer number (20425607424027).

Almost surely, 240851214848053 is an apocalyptic number.

It is an amenable number.

40851214848053 is a deficient number, since it is larger than the sum of its proper divisors (1).

40851214848053 is an equidigital number, since it uses as much as digits as its factorization.

40851214848053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4915200, while the sum is 53.

The spelling of 40851214848053 in words is "forty trillion, eight hundred fifty-one billion, two hundred fourteen million, eight hundred forty-eight thousand, fifty-three".