Base | Representation |
---|---|
bin | 111011101100100000101… |
… | …100100010010010110111 |
3 | 112112011121022122100220021 |
4 | 323230200230202102313 |
5 | 1014202343013012044 |
6 | 12420313305350011 |
7 | 602243250222346 |
oct | 73544054422267 |
9 | 15464538570807 |
10 | 4102242313399 |
11 | 1341829927a3a |
12 | 563060798307 |
13 | 239abc033329 |
14 | 10279a0d3b5d |
15 | 71a96ebde84 |
hex | 3bb20b224b7 |
4102242313399 has 2 divisors, whose sum is σ = 4102242313400. Its totient is φ = 4102242313398.
The previous prime is 4102242313397. The next prime is 4102242313423. The reversal of 4102242313399 is 9933132422014.
4102242313399 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4102242313399 - 21 = 4102242313397 is a prime.
Together with 4102242313397, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4102242313397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2051121156699 + 2051121156700.
It is an arithmetic number, because the mean of its divisors is an integer number (2051121156700).
Almost surely, 24102242313399 is an apocalyptic number.
4102242313399 is a deficient number, since it is larger than the sum of its proper divisors (1).
4102242313399 is an equidigital number, since it uses as much as digits as its factorization.
4102242313399 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 279936, while the sum is 43.
The spelling of 4102242313399 in words is "four trillion, one hundred two billion, two hundred forty-two million, three hundred thirteen thousand, three hundred ninety-nine".
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