4102242315113 has 2 divisors, whose sum is σ = 4102242315114. Its totient is φ = 4102242315112.

The previous prime is 4102242315089. The next prime is 4102242315137. The reversal of 4102242315113 is 3115132422014.

It is a happy number.

4102242315113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (4102242315089) and next prime (4102242315137).

It can be written as a sum of positive squares in only one way, i.e., 2339911724329 + 1762330590784 = 1529677^2 + 1327528^2 .

It is a cyclic number.

It is not a de Polignac number, because 4102242315113 - 2¹² = 4102242311017 is a prime.

It is a super-3 number, since 3×4102242315113³ (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (4102242365113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2051121157556 + 2051121157557.

It is an arithmetic number, because the mean of its divisors is an integer number (2051121157557).

Almost surely, 2^{4102242315113} is an apocalyptic number.

It is an amenable number.

4102242315113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4102242315113 is an equidigital number, since it uses as much as digits as its factorization.

4102242315113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 4102242315113 its reverse (3115132422014), we get a palindrome (7217374737127).

The spelling of 4102242315113 in words is "four trillion, one hundred two billion, two hundred forty-two million, three hundred fifteen thousand, one hundred thirteen".