Base | Representation |
---|---|
bin | 10010101010001100000101… |
… | …00101011100110100001000 |
3 | 12101021121210120021101112201 |
4 | 21111012002211130310020 |
5 | 20334232030414342440 |
6 | 223133502521445544 |
7 | 11433315354354652 |
oct | 1125060245346410 |
9 | 171247716241481 |
10 | 41032013434120 |
11 | 1208a640976935 |
12 | 47283423408b4 |
13 | 19b83c10c7417 |
14 | a1bd625216d2 |
15 | 4b250bc2519a |
hex | 25518295cd08 |
41032013434120 has 64 divisors (see below), whose sum is σ = 93469345079040. Its totient is φ = 16208986444800.
The previous prime is 41032013434103. The next prime is 41032013434127. The reversal of 41032013434120 is 2143431023014.
It is a happy number.
It is a super-2 number, since 2×410320134341202 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (41032013434127) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6554160 + ... + 11181280.
It is an arithmetic number, because the mean of its divisors is an integer number (1460458516860).
Almost surely, 241032013434120 is an apocalyptic number.
41032013434120 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 41032013434120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (46734672539520).
41032013434120 is an abundant number, since it is smaller than the sum of its proper divisors (52437331644920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41032013434120 is a wasteful number, since it uses less digits than its factorization.
41032013434120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4629886 (or 4629882 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 41032013434120 its reverse (2143431023014), we get a palindrome (43175444457134).
The spelling of 41032013434120 in words is "forty-one trillion, thirty-two billion, thirteen million, four hundred thirty-four thousand, one hundred twenty".
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