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41063111540471 is a prime number
BaseRepresentation
bin10010101011000110000000…
…01011010011111011110111
312101101121001211211212122102
421111203000023103323313
520340234223023243341
6223200044422052315
711435466120042026
oct1125430013237367
9171347054755572
1041063111540471
11120a1849a51479
124732380b7a09b
1319bb308b29297
14a1d6727348bd
154b322be5dc9b
hex2558c02d3ef7

41063111540471 has 2 divisors, whose sum is σ = 41063111540472. Its totient is φ = 41063111540470.

The previous prime is 41063111540389. The next prime is 41063111540513. The reversal of 41063111540471 is 17404511136014.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41063111540471 - 222 = 41063107346167 is a prime.

It is a super-3 number, since 3×410631115404713 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41063111545471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20531555770235 + 20531555770236.

It is an arithmetic number, because the mean of its divisors is an integer number (20531555770236).

Almost surely, 241063111540471 is an apocalyptic number.

41063111540471 is a deficient number, since it is larger than the sum of its proper divisors (1).

41063111540471 is an equidigital number, since it uses as much as digits as its factorization.

41063111540471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 38.

Adding to 41063111540471 its reverse (17404511136014), we get a palindrome (58467622676485).

The spelling of 41063111540471 in words is "forty-one trillion, sixty-three billion, one hundred eleven million, five hundred forty thousand, four hundred seventy-one".