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411012320317 is a prime number
BaseRepresentation
bin1011111101100100011…
…11100100110000111101
31110021220011012012112021
411332302033210300331
523213223123222232
6512452204240141
741460161036104
oct5766217446075
91407804165467
10411012320317
11149344815675
12677a7240051
132c9b1c8a701
1415c7095d03b
15aa585bd397
hex5fb23e4c3d

411012320317 has 2 divisors, whose sum is σ = 411012320318. Its totient is φ = 411012320316.

The previous prime is 411012320311. The next prime is 411012320339. The reversal of 411012320317 is 713023210114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 300749140836 + 110263179481 = 548406^2 + 332059^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-411012320317 is a prime.

It is a super-2 number, since 2×4110123203172 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 411012320291 and 411012320300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411012320311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205506160158 + 205506160159.

It is an arithmetic number, because the mean of its divisors is an integer number (205506160159).

Almost surely, 2411012320317 is an apocalyptic number.

It is an amenable number.

411012320317 is a deficient number, since it is larger than the sum of its proper divisors (1).

411012320317 is an equidigital number, since it uses as much as digits as its factorization.

411012320317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

The spelling of 411012320317 in words is "four hundred eleven billion, twelve million, three hundred twenty thousand, three hundred seventeen".