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4110132020 = 2251063193327
BaseRepresentation
bin1111010011111011…
…1010001100110100
3101121102221100011212
43310332322030310
531404143211040
61515502220552
7203565355121
oct36476721464
911542840155
104110132020
11181a076025
12968584758
135066a1ba7
142adc21748
15190c7bd65
hexf4fba334

4110132020 has 24 divisors (see below), whose sum is σ = 8639441664. Its totient is φ = 1642497696.

The previous prime is 4110132001. The next prime is 4110132107. The reversal of 4110132020 is 202310114.

It is a junction number, because it is equal to n+sod(n) for n = 4110131986 and 4110132004.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75404 + ... + 117923.

It is an arithmetic number, because the mean of its divisors is an integer number (359976736).

Almost surely, 24110132020 is an apocalyptic number.

It is an amenable number.

4110132020 is an abundant number, since it is smaller than the sum of its proper divisors (4529309644).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4110132020 is a wasteful number, since it uses less digits than its factorization.

4110132020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 194399 (or 194397 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 4110132020 is about 64110.3113391286. The cubic root of 4110132020 is about 1601.8379945723.

Adding to 4110132020 its reverse (202310114), we get a palindrome (4312442134).

The spelling of 4110132020 in words is "four billion, one hundred ten million, one hundred thirty-two thousand, twenty".

Divisors: 1 2 4 5 10 20 1063 2126 4252 5315 10630 21260 193327 386654 773308 966635 1933270 3866540 205506601 411013202 822026404 1027533005 2055066010 4110132020