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41101444151 is a prime number
BaseRepresentation
bin100110010001110101…
…100100010000110111
310221002102121200211022
4212101311210100313
51133133432203101
630514242331355
72653350340145
oct462165442067
9127072550738
1041101444151
111648176a369
127b70959b5b
133b5031a671
141dbc9a4595
151108555a1b
hex991d64437

41101444151 has 2 divisors, whose sum is σ = 41101444152. Its totient is φ = 41101444150.

The previous prime is 41101444079. The next prime is 41101444171. The reversal of 41101444151 is 15144410114.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41101444151 - 210 = 41101443127 is a prime.

It is a super-2 number, since 2×411014441512 (a number of 22 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 41101444151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41101444171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20550722075 + 20550722076.

It is an arithmetic number, because the mean of its divisors is an integer number (20550722076).

Almost surely, 241101444151 is an apocalyptic number.

41101444151 is a deficient number, since it is larger than the sum of its proper divisors (1).

41101444151 is an equidigital number, since it uses as much as digits as its factorization.

41101444151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1280, while the sum is 26.

Adding to 41101444151 its reverse (15144410114), we get a palindrome (56245854265).

The spelling of 41101444151 in words is "forty-one billion, one hundred one million, four hundred forty-four thousand, one hundred fifty-one".