411049231 has 4 divisors (see below), whose sum is σ = 421074864. Its totient is φ = 401023600.

The previous prime is 411049213. The next prime is 411049241. The reversal of 411049231 is 132940114.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 132940114 = 2 ⋅66470057.

It is a cyclic number.

It is not a de Polignac number, because 411049231 - 2⁹ = 411048719 is a prime.

It is a super-2 number, since 2×411049231² = 337922940611382722, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 411049196 and 411049205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411049201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5012755 + ... + 5012836.

It is an arithmetic number, because the mean of its divisors is an integer number (105268716).

Almost surely, 2^411049231 is an apocalyptic number.

411049231 is a gapful number since it is divisible by the number (41) formed by its first and last digit.

411049231 is a deficient number, since it is larger than the sum of its proper divisors (10025633).

411049231 is a wasteful number, since it uses less digits than its factorization.

411049231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10025632.

The product of its (nonzero) digits is 864, while the sum is 25.

The square root of 411049231 is about 20274.3490894282. The cubic root of 411049231 is about 743.5290592843.

Adding to 411049231 its reverse (132940114), we get a palindrome (543989345).

The spelling of 411049231 in words is "four hundred eleven million, forty-nine thousand, two hundred thirty-one".