Base | Representation |
---|---|
bin | 1011111101101111000… |
… | …10101010101001010111 |
3 | 1110022010100110022221001 |
4 | 11332313202222221113 |
5 | 23213413402224343 |
6 | 512505101404131 |
7 | 41462320432213 |
oct | 5766742525127 |
9 | 1408110408831 |
10 | 411101211223 |
11 | 14938aa0972a |
12 | 67810b69647 |
13 | 2c9c7511891 |
14 | 15c7c69b943 |
15 | aa612cb44d |
hex | 5fb78aaa57 |
411101211223 has 2 divisors, whose sum is σ = 411101211224. Its totient is φ = 411101211222.
The previous prime is 411101211211. The next prime is 411101211229. The reversal of 411101211223 is 322112101114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 411101211223 - 213 = 411101203031 is a prime.
It is a super-2 number, since 2×4111012112232 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 411101211223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411101211229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205550605611 + 205550605612.
It is an arithmetic number, because the mean of its divisors is an integer number (205550605612).
Almost surely, 2411101211223 is an apocalyptic number.
411101211223 is a deficient number, since it is larger than the sum of its proper divisors (1).
411101211223 is an equidigital number, since it uses as much as digits as its factorization.
411101211223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 411101211223 its reverse (322112101114), we get a palindrome (733213312337).
The spelling of 411101211223 in words is "four hundred eleven billion, one hundred one million, two hundred eleven thousand, two hundred twenty-three".
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