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4111211231 is a prime number
BaseRepresentation
bin1111010100001100…
…0001101011011111
3101121111222011120122
43311003001223133
531404432224411
61515541305155
7203610501401
oct36503015337
911544864518
104111211231
11181a742936
12968a051bb
1350698c18a
142b0022b71
15190de19db
hexf50c1adf

4111211231 has 2 divisors, whose sum is σ = 4111211232. Its totient is φ = 4111211230.

The previous prime is 4111211207. The next prime is 4111211233. The reversal of 4111211231 is 1321121114.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4111211231 is a prime.

It is a super-2 number, since 2×41112112312 = 33804115571801070722, which contains 22 as substring.

Together with 4111211233, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4111211233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055605615 + 2055605616.

It is an arithmetic number, because the mean of its divisors is an integer number (2055605616).

Almost surely, 24111211231 is an apocalyptic number.

4111211231 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111211231 is an equidigital number, since it uses as much as digits as its factorization.

4111211231 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48, while the sum is 17.

The square root of 4111211231 is about 64118.7276152607. The cubic root of 4111211231 is about 1601.9781822753.

Adding to 4111211231 its reverse (1321121114), we get a palindrome (5432332345).

The spelling of 4111211231 in words is "four billion, one hundred eleven million, two hundred eleven thousand, two hundred thirty-one".