Search a number
-
+
41113683813437 is a prime number
BaseRepresentation
bin10010101100100100001101…
…00001001110010000111101
312101120102121022111112012022
421112102012201032100331
520342101311024012222
6223235210545245525
711442236261213054
oct1126220641162075
9171512538445168
1041113683813437
1112111240754694
1247401356338a5
1319c3008307361
14a21cad07139b
154b46dbb96042
hex25648684e43d

41113683813437 has 2 divisors, whose sum is σ = 41113683813438. Its totient is φ = 41113683813436.

The previous prime is 41113683813403. The next prime is 41113683813497. The reversal of 41113683813437 is 73431838631114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 27017758975321 + 14095924838116 = 5197861^2 + 3754454^2 .

It is a cyclic number.

It is not a de Polignac number, because 41113683813437 - 216 = 41113683747901 is a prime.

It is a super-3 number, since 3×411136838134373 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41113683813497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20556841906718 + 20556841906719.

It is an arithmetic number, because the mean of its divisors is an integer number (20556841906719).

Almost surely, 241113683813437 is an apocalyptic number.

It is an amenable number.

41113683813437 is a deficient number, since it is larger than the sum of its proper divisors (1).

41113683813437 is an equidigital number, since it uses as much as digits as its factorization.

41113683813437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3483648, while the sum is 53.

The spelling of 41113683813437 in words is "forty-one trillion, one hundred thirteen billion, six hundred eighty-three million, eight hundred thirteen thousand, four hundred thirty-seven".