41115300493 has 2 divisors, whose sum is σ = 41115300494. Its totient is φ = 41115300492.

The previous prime is 41115300433. The next prime is 41115300509. The reversal of 41115300493 is 39400351114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39005460004 + 2109840489 = 197498^2 + 45933^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41115300493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41115300433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20557650246 + 20557650247.

It is an arithmetic number, because the mean of its divisors is an integer number (20557650247).

Almost surely, 2^41115300493 is an apocalyptic number.

It is an amenable number.

41115300493 is a deficient number, since it is larger than the sum of its proper divisors (1).

41115300493 is an equidigital number, since it uses as much as digits as its factorization.

41115300493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 31.

The spelling of 41115300493 in words is "forty-one billion, one hundred fifteen million, three hundred thousand, four hundred ninety-three".