Base | Representation |
---|---|
bin | 100110010011000001… |
… | …100000000110110111 |
3 | 10221010211002000121121 |
4 | 212103001200012313 |
5 | 1133204031200241 |
6 | 30520233124411 |
7 | 2654011464664 |
oct | 462301400667 |
9 | 127124060547 |
10 | 41121350071 |
11 | 16491a25a3a |
12 | 7b77559707 |
13 | 3b5449a009 |
14 | 1dc14a6a6b |
15 | 110a188ad1 |
hex | 9930601b7 |
41121350071 has 2 divisors, whose sum is σ = 41121350072. Its totient is φ = 41121350070.
The previous prime is 41121350051. The next prime is 41121350129. The reversal of 41121350071 is 17005312114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41121350071 - 213 = 41121341879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41121350051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20560675035 + 20560675036.
It is an arithmetic number, because the mean of its divisors is an integer number (20560675036).
Almost surely, 241121350071 is an apocalyptic number.
41121350071 is a deficient number, since it is larger than the sum of its proper divisors (1).
41121350071 is an equidigital number, since it uses as much as digits as its factorization.
41121350071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 840, while the sum is 25.
Adding to 41121350071 its reverse (17005312114), we get a palindrome (58126662185).
The spelling of 41121350071 in words is "forty-one billion, one hundred twenty-one million, three hundred fifty thousand, seventy-one".
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