4112304213371 has 2 divisors, whose sum is σ = 4112304213372. Its totient is φ = 4112304213370.

The previous prime is 4112304213337. The next prime is 4112304213373. The reversal of 4112304213371 is 1733124032114.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4112304213371 is a prime.

It is a super-2 number, since 2×4112304213371² (a number of 26 digits) contains 22 as substring.

Together with 4112304213373, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4112304213373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056152106685 + 2056152106686.

It is an arithmetic number, because the mean of its divisors is an integer number (2056152106686).

Almost surely, 2^{4112304213371} is an apocalyptic number.

4112304213371 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112304213371 is an equidigital number, since it uses as much as digits as its factorization.

4112304213371 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 32.

Adding to 4112304213371 its reverse (1733124032114), we get a palindrome (5845428245485).

The spelling of 4112304213371 in words is "four trillion, one hundred twelve billion, three hundred four million, two hundred thirteen thousand, three hundred seventy-one".