41124401471 has 2 divisors, whose sum is σ = 41124401472. Its totient is φ = 41124401470.

The previous prime is 41124401443. The next prime is 41124401473. The reversal of 41124401471 is 17410442114.

41124401471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41124401471 - 2⁶ = 41124401407 is a prime.

It is a super-3 number, since 3×41124401471³ (a number of 33 digits) contains 333 as substring.

Together with 41124401473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41124401473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20562200735 + 20562200736.

It is an arithmetic number, because the mean of its divisors is an integer number (20562200736).

Almost surely, 2^41124401471 is an apocalyptic number.

41124401471 is a deficient number, since it is larger than the sum of its proper divisors (1).

41124401471 is an equidigital number, since it uses as much as digits as its factorization.

41124401471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3584, while the sum is 29.

Adding to 41124401471 its reverse (17410442114), we get a palindrome (58534843585).

The spelling of 41124401471 in words is "forty-one billion, one hundred twenty-four million, four hundred one thousand, four hundred seventy-one".