Base | Representation |
---|---|
bin | 111011110110000000101… |
… | …110010101001011100100 |
3 | 112120010221020122202202002 |
4 | 323312000232111023210 |
5 | 1014334240443100200 |
6 | 12425121432504432 |
7 | 603054115361333 |
oct | 73660056251344 |
9 | 15503836582662 |
10 | 4112443331300 |
11 | 134609405a747 |
12 | 565028b4b118 |
13 | 23aa565731b5 |
14 | 103086c21d1a |
15 | 71e92837bd5 |
hex | 3bd80b952e4 |
4112443331300 has 72 divisors (see below), whose sum is σ = 9328479605760. Its totient is φ = 1571762649600.
The previous prime is 4112443331273. The next prime is 4112443331327. The reversal of 4112443331300 is 31333442114.
It is a happy number.
4112443331300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (4112443331273) and next prime (4112443331327).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8151269 + ... + 8641068.
Almost surely, 24112443331300 is an apocalyptic number.
It is an amenable number.
4112443331300 is an abundant number, since it is smaller than the sum of its proper divisors (5216036274460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4112443331300 is a wasteful number, since it uses less digits than its factorization.
4112443331300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16792461 (or 16792454 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 4112443331300 its reverse (31333442114), we get a palindrome (4143776773414).
The spelling of 4112443331300 in words is "four trillion, one hundred twelve billion, four hundred forty-three million, three hundred thirty-one thousand, three hundred".
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