4112551130124 has 12 divisors (see below), whose sum is σ = 9595952636984. Its totient is φ = 1370850376704.

The previous prime is 4112551130099. The next prime is 4112551130159. The reversal of 4112551130124 is 4210311552114.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-3 number, since 3×4112551130124³ (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4112551130091 and 4112551130100.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171356297077 + ... + 171356297100.

Almost surely, 2^{4112551130124} is an apocalyptic number.

It is an amenable number.

4112551130124 is an abundant number, since it is smaller than the sum of its proper divisors (5483401506860).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4112551130124 is a wasteful number, since it uses less digits than its factorization.

4112551130124 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 342712594184 (or 342712594182 counting only the distinct ones).

The product of its (nonzero) digits is 4800, while the sum is 30.

Adding to 4112551130124 its reverse (4210311552114), we get a palindrome (8322862682238).

The spelling of 4112551130124 in words is "four trillion, one hundred twelve billion, five hundred fifty-one million, one hundred thirty thousand, one hundred twenty-four".