Base | Representation |
---|---|
bin | 10010101101000010100111… |
… | …11000110111101101001111 |
3 | 12101121222202102002100001102 |
4 | 21112201103320313231033 |
5 | 20342333232121244123 |
6 | 223250511231133315 |
7 | 11443355044452602 |
oct | 1126412370675517 |
9 | 171558672070042 |
10 | 41130014243663 |
11 | 12118160868614 |
12 | 474333267423b |
13 | 19c470b684117 |
14 | a229bbc58339 |
15 | 4b4d456ac028 |
hex | 256853e37b4f |
41130014243663 has 2 divisors, whose sum is σ = 41130014243664. Its totient is φ = 41130014243662.
The previous prime is 41130014243587. The next prime is 41130014243723. The reversal of 41130014243663 is 36634241003114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41130014243663 - 230 = 41128940501839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41130014240663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20565007121831 + 20565007121832.
It is an arithmetic number, because the mean of its divisors is an integer number (20565007121832).
Almost surely, 241130014243663 is an apocalyptic number.
41130014243663 is a deficient number, since it is larger than the sum of its proper divisors (1).
41130014243663 is an equidigital number, since it uses as much as digits as its factorization.
41130014243663 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 38.
Adding to 41130014243663 its reverse (36634241003114), we get a palindrome (77764255246777).
The spelling of 41130014243663 in words is "forty-one trillion, one hundred thirty billion, fourteen million, two hundred forty-three thousand, six hundred sixty-three".
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