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4113045151 is a prime number
BaseRepresentation
bin1111010100101000…
…0001011010011111
3101121122102100020121
43311022001122133
531410414421101
61520044455411
7203632210165
oct36512013237
911548370217
104113045151
111820785776
1296954a567
13507181b37
142b037d235
151911550a1
hexf528169f

4113045151 has 2 divisors, whose sum is σ = 4113045152. Its totient is φ = 4113045150.

The previous prime is 4113045137. The next prime is 4113045191. The reversal of 4113045151 is 1515403114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4113045151 - 215 = 4113012383 is a prime.

It is a super-2 number, since 2×41130451512 = 33834280828329225602, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4113045191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056522575 + 2056522576.

It is an arithmetic number, because the mean of its divisors is an integer number (2056522576).

Almost surely, 24113045151 is an apocalyptic number.

4113045151 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113045151 is an equidigital number, since it uses as much as digits as its factorization.

4113045151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 25.

The square root of 4113045151 is about 64133.0269907791. The cubic root of 4113045151 is about 1602.2163491583.

Adding to 4113045151 its reverse (1515403114), we get a palindrome (5628448265).

The spelling of 4113045151 in words is "four billion, one hundred thirteen million, forty-five thousand, one hundred fifty-one".