Base | Representation |
---|---|
bin | 111011110110100101000… |
… | …100000100100110101011 |
3 | 112120012111201212200011112 |
4 | 323312211010010212223 |
5 | 1014342013032312342 |
6 | 12425302132220535 |
7 | 603105200512301 |
oct | 73664504044653 |
9 | 15505451780145 |
10 | 4113053010347 |
11 | 1346377219626 |
12 | 56517916a74b |
13 | 23ab2297a528 |
14 | 103103ba8271 |
15 | 71ecb118682 |
hex | 3bda51049ab |
4113053010347 has 2 divisors, whose sum is σ = 4113053010348. Its totient is φ = 4113053010346.
The previous prime is 4113053010293. The next prime is 4113053010371. The reversal of 4113053010347 is 7430103503114.
4113053010347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4113053010347 - 222 = 4113048816043 is a prime.
It is not a weakly prime, because it can be changed into another prime (4113053012347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056526505173 + 2056526505174.
It is an arithmetic number, because the mean of its divisors is an integer number (2056526505174).
Almost surely, 24113053010347 is an apocalyptic number.
4113053010347 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113053010347 is an equidigital number, since it uses as much as digits as its factorization.
4113053010347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 32.
The spelling of 4113053010347 in words is "four trillion, one hundred thirteen billion, fifty-three million, ten thousand, three hundred forty-seven".
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