4113053010371 has 2 divisors, whose sum is σ = 4113053010372. Its totient is φ = 4113053010370.

The previous prime is 4113053010347. The next prime is 4113053010373. The reversal of 4113053010371 is 1730103503114.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4113053010371 - 2¹⁰ = 4113053009347 is a prime.

It is a super-2 number, since 2×4113053010371² (a number of 26 digits) contains 22 as substring.

Together with 4113053010373, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4113053010373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056526505185 + 2056526505186.

It is an arithmetic number, because the mean of its divisors is an integer number (2056526505186).

Almost surely, 2^{4113053010371} is an apocalyptic number.

4113053010371 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113053010371 is an equidigital number, since it uses as much as digits as its factorization.

4113053010371 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3780, while the sum is 29.

Adding to 4113053010371 its reverse (1730103503114), we get a palindrome (5843156513485).

The spelling of 4113053010371 in words is "four trillion, one hundred thirteen billion, fifty-three million, ten thousand, three hundred seventy-one".