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4113100314402 = 23685516719067
BaseRepresentation
bin111011110110100111111…
…000100001011100100010
3112120012122000212222010120
4323312213320201130202
51014342112140030102
612425310542141110
7603106313551062
oct73664770413442
915505560788116
104113100314402
1113463a0998892
12565190b81796
1323ab2c7007b1
1410310a19d3a2
1571ed035e6bc
hex3bda7e21722

4113100314402 has 8 divisors (see below), whose sum is σ = 8226200628816. Its totient is φ = 1371033438132.

The previous prime is 4113100314397. The next prime is 4113100314437. The reversal of 4113100314402 is 2044130013114.

It is a sphenic number, since it is the product of 3 distinct primes.

4113100314402 is an admirable number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 342758359528 + ... + 342758359539.

It is an arithmetic number, because the mean of its divisors is an integer number (1028275078602).

Almost surely, 24113100314402 is an apocalyptic number.

4113100314402 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4113100314402 is a wasteful number, since it uses less digits than its factorization.

4113100314402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 685516719072.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 4113100314402 its reverse (2044130013114), we get a palindrome (6157230327516).

The spelling of 4113100314402 in words is "four trillion, one hundred thirteen billion, one hundred million, three hundred fourteen thousand, four hundred two".

Divisors: 1 2 3 6 685516719067 1371033438134 2056550157201 4113100314402