Base | Representation |
---|---|
bin | 111011110110100111111… |
… | …000100001011101000101 |
3 | 112120012122000212222011212 |
4 | 323312213320201131011 |
5 | 1014342112140030222 |
6 | 12425310542141205 |
7 | 603106313551142 |
oct | 73664770413505 |
9 | 15505560788155 |
10 | 4113100314437 |
11 | 13463a0998914 |
12 | 565190b81805 |
13 | 23ab2c70080a |
14 | 10310a19d3c9 |
15 | 71ed035e6e2 |
hex | 3bda7e21745 |
4113100314437 has 2 divisors, whose sum is σ = 4113100314438. Its totient is φ = 4113100314436.
The previous prime is 4113100314397. The next prime is 4113100314481. The reversal of 4113100314437 is 7344130013114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2735272745956 + 1377827568481 = 1653866^2 + 1173809^2 .
It is a cyclic number.
It is not a de Polignac number, because 4113100314437 - 218 = 4113100052293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4113100314737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056550157218 + 2056550157219.
It is an arithmetic number, because the mean of its divisors is an integer number (2056550157219).
Almost surely, 24113100314437 is an apocalyptic number.
It is an amenable number.
4113100314437 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113100314437 is an equidigital number, since it uses as much as digits as its factorization.
4113100314437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
The spelling of 4113100314437 in words is "four trillion, one hundred thirteen billion, one hundred million, three hundred fourteen thousand, four hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •