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4113100314403 = 19725781240007
BaseRepresentation
bin111011110110100111111…
…000100001011100100011
3112120012122000212222010121
4323312213320201130203
51014342112140030103
612425310542141111
7603106313551063
oct73664770413443
915505560788117
104113100314403
1113463a0998893
12565190b81797
1323ab2c7007b2
1410310a19d3a3
1571ed035e6bd
hex3bda7e21723

4113100314403 has 8 divisors (see below), whose sum is σ = 4150064568672. Its totient is φ = 4076298541056.

The previous prime is 4113100314397. The next prime is 4113100314437. The reversal of 4113100314403 is 3044130013114.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4113100314403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4113100314493) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40569375 + ... + 40670632.

It is an arithmetic number, because the mean of its divisors is an integer number (518758071084).

Almost surely, 24113100314403 is an apocalyptic number.

4113100314403 is a deficient number, since it is larger than the sum of its proper divisors (36964254269).

4113100314403 is a wasteful number, since it uses less digits than its factorization.

4113100314403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81240461.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4113100314403 its reverse (3044130013114), we get a palindrome (7157230327517).

The spelling of 4113100314403 in words is "four trillion, one hundred thirteen billion, one hundred million, three hundred fourteen thousand, four hundred three".

Divisors: 1 197 257 50629 81240007 16004281379 20878681799 4113100314403