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411315103 is a prime number
BaseRepresentation
bin11000100001000…
…010101110011111
31001122221222020201
4120201002232133
51320244040403
6104451524331
713123056253
oct3041025637
91048858221
10411315103
111a11a4141
12b58b96a7
13672a3924
143c8ac263
152619b21d
hex18842b9f

411315103 has 2 divisors, whose sum is σ = 411315104. Its totient is φ = 411315102.

The previous prime is 411315101. The next prime is 411315143. The reversal of 411315103 is 301513114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 411315103 - 21 = 411315101 is a prime.

It is a super-2 number, since 2×4113151032 = 338360227911801218, which contains 22 as substring.

Together with 411315101, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411315101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205657551 + 205657552.

It is an arithmetic number, because the mean of its divisors is an integer number (205657552).

Almost surely, 2411315103 is an apocalyptic number.

411315103 is a deficient number, since it is larger than the sum of its proper divisors (1).

411315103 is an equidigital number, since it uses as much as digits as its factorization.

411315103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 411315103 is about 20280.9048861238. The cubic root of 411315103 is about 743.6893328290.

Adding to 411315103 its reverse (301513114), we get a palindrome (712828217).

The spelling of 411315103 in words is "four hundred eleven million, three hundred fifteen thousand, one hundred three".