Base | Representation |
---|---|
bin | 111011110110110000010… |
… | …010110011100110101101 |
3 | 112120012222212101222201021 |
4 | 323312300102303212231 |
5 | 1014342404301003003 |
6 | 12425332542414141 |
7 | 603112646134165 |
oct | 73666022634655 |
9 | 15505885358637 |
10 | 4113241422253 |
11 | 1346463607247 |
12 | 565210291351 |
13 | 23ab52a08172 |
14 | 103120c115a5 |
15 | 71edc9342bd |
hex | 3bdb04b39ad |
4113241422253 has 2 divisors, whose sum is σ = 4113241422254. Its totient is φ = 4113241422252.
The previous prime is 4113241422149. The next prime is 4113241422259. The reversal of 4113241422253 is 3522241423114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2886149083689 + 1227092338564 = 1698867^2 + 1107742^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4113241422253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4113241422259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056620711126 + 2056620711127.
It is an arithmetic number, because the mean of its divisors is an integer number (2056620711127).
Almost surely, 24113241422253 is an apocalyptic number.
It is an amenable number.
4113241422253 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113241422253 is an equidigital number, since it uses as much as digits as its factorization.
4113241422253 is an evil number, because the sum of its binary digits is even.
The product of its digits is 46080, while the sum is 34.
Adding to 4113241422253 its reverse (3522241423114), we get a palindrome (7635482845367).
The spelling of 4113241422253 in words is "four trillion, one hundred thirteen billion, two hundred forty-one million, four hundred twenty-two thousand, two hundred fifty-three".
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