Base | Representation |
---|---|
bin | 101110110000110001110110… |
… | …0111111101100000110010000 |
3 | 1222221101020011221111200001201 |
4 | 1131201203230333230012100 |
5 | 412403114334423401000 |
6 | 4014451453404440544 |
7 | 152432131115512135 |
oct | 13541435477540620 |
9 | 1887336157450051 |
10 | 411324404122000 |
11 | 10a073777a15976 |
12 | 3a171512849154 |
13 | 14868956722585 |
14 | 73802c90b658c |
15 | 32847596b296a |
hex | 17618ecfec190 |
411324404122000 has 80 divisors (see below), whose sum is σ = 994587354513792. Its totient is φ = 164528943561600.
The previous prime is 411324404121947. The next prime is 411324404122039. The reversal of 411324404122000 is 221404423114.
It is a tau number, because it is divible by the number of its divisors (80).
It is a self number, because there is not a number n which added to its sum of digits gives 411324404122000.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 549920269 + ... + 550667731.
Almost surely, 2411324404122000 is an apocalyptic number.
411324404122000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
411324404122000 is an abundant number, since it is smaller than the sum of its proper divisors (583262950391792).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
411324404122000 is a wasteful number, since it uses less digits than its factorization.
411324404122000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1022633 (or 1022617 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 411324404122000 its reverse (221404423114), we get a palindrome (411545808545114).
The spelling of 411324404122000 in words is "four hundred eleven trillion, three hundred twenty-four billion, four hundred four million, one hundred twenty-two thousand".
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