4113300402331 has 2 divisors, whose sum is σ = 4113300402332. Its totient is φ = 4113300402330.

The previous prime is 4113300402329. The next prime is 4113300402427. The reversal of 4113300402331 is 1332040033114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4113300402331 - 2¹ = 4113300402329 is a prime.

It is a super-2 number, since 2×4113300402331² (a number of 26 digits) contains 22 as substring.

Together with 4113300402329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 4113300402296 and 4113300402305.

It is not a weakly prime, because it can be changed into another prime (4113300408331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056650201165 + 2056650201166.

It is an arithmetic number, because the mean of its divisors is an integer number (2056650201166).

Almost surely, 2^{4113300402331} is an apocalyptic number.

4113300402331 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113300402331 is an equidigital number, since it uses as much as digits as its factorization.

4113300402331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 4113300402331 its reverse (1332040033114), we get a palindrome (5445340435445).

The spelling of 4113300402331 in words is "four trillion, one hundred thirteen billion, three hundred million, four hundred two thousand, three hundred thirty-one".