Base | Representation |
---|---|
bin | 111011110110110011110… |
… | …011110111011010000000 |
3 | 112120020010222102101201022 |
4 | 323312303303313122000 |
5 | 1014343014401421344 |
6 | 12425342451125012 |
7 | 603114263456012 |
oct | 73666363673200 |
9 | 15506128371638 |
10 | 4113300420224 |
11 | 13464939432a6 |
12 | 565227ba3768 |
13 | 23ab61cc3cc8 |
14 | 1031289ac1b2 |
15 | 71ee2bda0ee |
hex | 3bdb3cf7680 |
4113300420224 has 32 divisors (see below), whose sum is σ = 8204027703300. Its totient is φ = 2054250330112.
The previous prime is 4113300420209. The next prime is 4113300420269. The reversal of 4113300420224 is 4220240033114.
It can be written as a sum of positive squares in 2 ways, for example, as 3821086657600 + 292213762624 = 1954760^2 + 540568^2 .
It is a tau number, because it is divible by the number of its divisors (32).
It is a junction number, because it is equal to n+sod(n) for n = 4113300420193 and 4113300420202.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18638939 + ... + 18858330.
Almost surely, 24113300420224 is an apocalyptic number.
It is an amenable number.
4113300420224 is a deficient number, since it is larger than the sum of its proper divisors (4090727283076).
4113300420224 is an equidigital number, since it uses as much as digits as its factorization.
4113300420224 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37498140 (or 37498128 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 4113300420224 its reverse (4220240033114), we get a palindrome (8333540453338).
The spelling of 4113300420224 in words is "four trillion, one hundred thirteen billion, three hundred million, four hundred twenty thousand, two hundred twenty-four".
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