Base | Representation |
---|---|
bin | 1011111110001010011… |
… | …01000000011101011111 |
3 | 1110022201022202001121202 |
4 | 11333011031000131133 |
5 | 23214401041230211 |
6 | 512543530150115 |
7 | 41501102556146 |
oct | 5770515003537 |
9 | 1408638661552 |
10 | 411330414431 |
11 | 149498328472 |
12 | 6787588233b |
13 | 2ca32b52291 |
14 | 15ca0cc275d |
15 | aa764a353b |
hex | 5fc534075f |
411330414431 has 2 divisors, whose sum is σ = 411330414432. Its totient is φ = 411330414430.
The previous prime is 411330414377. The next prime is 411330414433. The reversal of 411330414431 is 134414033114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 411330414431 - 214 = 411330398047 is a prime.
It is a super-2 number, since 2×4113304144312 (a number of 24 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 411330414433, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 411330414394 and 411330414403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411330414433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205665207215 + 205665207216.
It is an arithmetic number, because the mean of its divisors is an integer number (205665207216).
Almost surely, 2411330414431 is an apocalyptic number.
411330414431 is a deficient number, since it is larger than the sum of its proper divisors (1).
411330414431 is an equidigital number, since it uses as much as digits as its factorization.
411330414431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 411330414431 its reverse (134414033114), we get a palindrome (545744447545).
The spelling of 411330414431 in words is "four hundred eleven billion, three hundred thirty million, four hundred fourteen thousand, four hundred thirty-one".
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