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41133140345501 is a prime number
BaseRepresentation
bin10010101101001000011100…
…01110000000001010011101
312101122021211021101202120222
421112210032032000022131
520342411132412024001
6223252145342251125
711443525364052251
oct1126441616001235
9171567737352528
1041133140345501
1112119515428156
124743a65586aa5
1319c4ab921aa19
14a22bd70c8261
154b4e79d5e61b
hex25690e38029d

41133140345501 has 2 divisors, whose sum is σ = 41133140345502. Its totient is φ = 41133140345500.

The previous prime is 41133140345431. The next prime is 41133140345537. The reversal of 41133140345501 is 10554304133114.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39602226580900 + 1530913764601 = 6293030^2 + 1237301^2 .

It is a cyclic number.

It is not a de Polignac number, because 41133140345501 - 214 = 41133140329117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41133140845501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20566570172750 + 20566570172751.

It is an arithmetic number, because the mean of its divisors is an integer number (20566570172751).

Almost surely, 241133140345501 is an apocalyptic number.

It is an amenable number.

41133140345501 is a deficient number, since it is larger than the sum of its proper divisors (1).

41133140345501 is an equidigital number, since it uses as much as digits as its factorization.

41133140345501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 41133140345501 its reverse (10554304133114), we get a palindrome (51687444478615).

The spelling of 41133140345501 in words is "forty-one trillion, one hundred thirty-three billion, one hundred forty million, three hundred forty-five thousand, five hundred one".