Search a number
-
+
4113340031401 is a prime number
BaseRepresentation
bin111011110110110110001…
…010111110000110101001
3112120020020201221212000221
4323312312022332012221
51014343110022001101
612425350424130041
7603115254244336
oct73666612760651
915506221855027
104113340031401
111346504238807
12565239306921
1323ab6a282883
1410312dd5d98d
1571ee6411aa1
hex3bdb62be1a9

4113340031401 has 2 divisors, whose sum is σ = 4113340031402. Its totient is φ = 4113340031400.

The previous prime is 4113340031393. The next prime is 4113340031443. The reversal of 4113340031401 is 1041300433114.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4054681613376 + 58658418025 = 2013624^2 + 242195^2 .

It is a cyclic number.

It is not a de Polignac number, because 4113340031401 - 23 = 4113340031393 is a prime.

It is not a weakly prime, because it can be changed into another prime (4113340031201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056670015700 + 2056670015701.

It is an arithmetic number, because the mean of its divisors is an integer number (2056670015701).

Almost surely, 24113340031401 is an apocalyptic number.

It is an amenable number.

4113340031401 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113340031401 is an equidigital number, since it uses as much as digits as its factorization.

4113340031401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4113340031401 its reverse (1041300433114), we get a palindrome (5154640464515).

The spelling of 4113340031401 in words is "four trillion, one hundred thirteen billion, three hundred forty million, thirty-one thousand, four hundred one".