Base | Representation |
---|---|
bin | 10010101101001000111100… |
… | …10111011000101000110111 |
3 | 12101122022112011010122200012 |
4 | 21112210132113120220313 |
5 | 20342412211234144003 |
6 | 223252232300410435 |
7 | 11443535163451511 |
oct | 1126443627305067 |
9 | 171568464118605 |
10 | 41133411240503 |
11 | 1211964433261a |
12 | 4743b20246a1b |
13 | 19c4b3039801a |
14 | a22c21082bb1 |
15 | 4b4e93a1e8d8 |
hex | 25691e5d8a37 |
41133411240503 has 2 divisors, whose sum is σ = 41133411240504. Its totient is φ = 41133411240502.
The previous prime is 41133411240497. The next prime is 41133411240527. The reversal of 41133411240503 is 30504211433114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41133411240503 - 238 = 40858533333559 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 41133411240503.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41133411240553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20566705620251 + 20566705620252.
It is an arithmetic number, because the mean of its divisors is an integer number (20566705620252).
Almost surely, 241133411240503 is an apocalyptic number.
41133411240503 is a deficient number, since it is larger than the sum of its proper divisors (1).
41133411240503 is an equidigital number, since it uses as much as digits as its factorization.
41133411240503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 41133411240503 its reverse (30504211433114), we get a palindrome (71637622673617).
The spelling of 41133411240503 in words is "forty-one trillion, one hundred thirty-three billion, four hundred eleven million, two hundred forty thousand, five hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •