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41133411240503 is a prime number
BaseRepresentation
bin10010101101001000111100…
…10111011000101000110111
312101122022112011010122200012
421112210132113120220313
520342412211234144003
6223252232300410435
711443535163451511
oct1126443627305067
9171568464118605
1041133411240503
111211964433261a
124743b20246a1b
1319c4b3039801a
14a22c21082bb1
154b4e93a1e8d8
hex25691e5d8a37

41133411240503 has 2 divisors, whose sum is σ = 41133411240504. Its totient is φ = 41133411240502.

The previous prime is 41133411240497. The next prime is 41133411240527. The reversal of 41133411240503 is 30504211433114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 41133411240503 - 238 = 40858533333559 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 41133411240503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41133411240553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20566705620251 + 20566705620252.

It is an arithmetic number, because the mean of its divisors is an integer number (20566705620252).

Almost surely, 241133411240503 is an apocalyptic number.

41133411240503 is a deficient number, since it is larger than the sum of its proper divisors (1).

41133411240503 is an equidigital number, since it uses as much as digits as its factorization.

41133411240503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 41133411240503 its reverse (30504211433114), we get a palindrome (71637622673617).

The spelling of 41133411240503 in words is "forty-one trillion, one hundred thirty-three billion, four hundred eleven million, two hundred forty thousand, five hundred three".